A basket contains six apples and five peaches. Three times, you randomly select a piece of fruit, return it to the basket, and then mix the fruit. All three times, the fruit is an apple. Find the probability of this occuring.

P( it occurring once) = 6/11

Now as the 3 events are independent we multiply the probs:-

P( apple picked 3 times) = 6/11 * 6/11 * 6/11 = 216/1331 or about 16.2%

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eudora eudora · Answer 2 · 2019-08-13T12:15:41+02:00

Answer:

16.22%

Step-by-step explanation:

A basket contains six apples and five peaches.

Total fruits in the basket = 6 + 5 = 11

The probability of selecting a piece of fruit is an apple [tex]P_{1}=\frac{6}{11}[/tex]

Now return it to the basket and select a fruit. so all events are independent.

Therefore, the probability of each time selecting an apple is same.

Probability=[tex]P_{1}\times P_{2}\times P_{3}[/tex]

P =[tex]\frac{6}{11}[/tex]× [tex]\frac{6}{11}[/tex]×[tex]\frac{6}{11}[/tex]

=[tex]\frac{216}{1331}[/tex] = 16.22%

The probability of all three times the fruit is an apple is 16.22%